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LuckyWell [14K]
3 years ago
8

4(4q + 8r) marked as BRAINLIEST:)

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

8q+32r

Step-by-step explanation:

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What power of 10 can you multiply 0.02 by to get a product of 20? Explain your answer.
viva [34]
10^1 = .2
10^2 = 2.0
10^3 = 20.0

So, the answer is 3.
7 0
3 years ago
Read 2 more answers
Which statements about residuals are true for the least-squares regression line? I. A random scattering of residuals indicates t
Daniel [21]

Answer:

II. The sum of the residuals is always 0.

Step-by-step explanation:

A least squares regression line is a standard technique in regression analysis used to make the vertical distance obtained from the data points running to the regression line to become very minimal or as small as possible.

For any least-squares regression line, the sum of the residuals is always zero.

Basically, residuals are used to measure or determine whether or not the line of regression is a good fit or match for the data by subtracting the difference between them i.e the predicted y value and the actual y value, for the x value respectively.

Hence, the statement about residuals which is true for the least-squares regression line is that the sum of the residuals is always zero (0).

7 0
3 years ago
Math 64 times40 eaquels 2.56
UkoKoshka [18]

Answer:

Wrong. It equals 2560.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
4 0
2 years ago
Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
I am Lyosha [343]

Answer:

|x   y   1|

|7  -3   1| = 0

|4  -8   1|

x*(-3*1 - (-8)*1) - y*(7*1 - 4*1) + 1*(7*-8 - 4*-3) = 0

5x - 3y - 44 = 0

Step-by-step explanation:

6 0
2 years ago
Y=x+1<br> y=x^2-1<br><br> please help i don't understand
ololo11 [35]

ANSWER

The solution is

(x=1,y=2),(x=2,y=3)


<u>EXPLANATION</u>

We have

y=x+1---(1)

and


y=x^2-1---(2)


Let us substitute equation (1) in to equation (2). This gives us,

x+1=x^2-1(2)

We rewrite this as a quadratic equation as the highest degree is 2.

x^2-x-1-1=0

This implies that


x^2-x-2=0


we factor to obtain,


x^2+x-2x-2=0


x(x-1)-2(x-1)=0


(x-1)(x-2)=0


This means,

(x-1)=0\:\: or\:\:(x-2)=0

x=1\:\: or\:\:x=2


We substitute this values into any of the above equations, preferably equation (1)


When, x=1, y=1+1=2


When, x=2, y=2+1=3


The solution is

(1,2),(2,3)


8 0
4 years ago
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