1-octodecyl-3-methylimidazoliumbis((trifluoromethyl)sulfonyl)imide/ACIL00078 can be provided in Alfa Chemistry. We are dedicated to provide our customers the best products and services. http://www.alfa-chemistry.com/1-octodecyl-3-methylimidazoliumbis-trifluoromethyl-sulfonyl-item-296261.htm
I believe proteins are synthesized from amino acids during synthesis reactions.
Protein synthesis starts with transcription of mRNA from a DNA gene in the nucleus.Various types of RNA may have been synthesized using the appropriate DNA. The RNAs migrate from the nucleus to the cytoplasm where the process of translation takes place. During the process the mRNA with the codons (three nucleotide bases that code for a specific amino acids) is interpreted by the anticodons in the tRNA , thus forming amino acids with together forms polypeptides and then proteins are formed.
Herbivore; carnivore
A rabbit is an example of a herbivore while a hyena is an example of a carnivore.
A herbivore is an animal that obtain its energy by feeding mainly on plants (i.e. that eats no meat). Other examples of herbivores apart from rabbit are cows, sheep and insects. A carnivore is an animal that feeds on meat as the main parts of its diet. Other examples of carnivores apart from hyena are lions, coyotes, tigers and eagles.
Microtubules are composed of two different types of tubulin. Namely, these simpler units are called alpha-tubulin and beta-tubulin. These subunits are essentially tightly bound together to form heterodimers. In the microtubule structure, they are arranged in an organized manner in such a way that they in parallel direction with protofilaments.
Answer:
C) 64% AA, 32% Aa, 4% aa
Explanation:
The frequency of dominant allele A is = 80% = 0.8
Since the population is in Hardy-Weinberg equilibrium, p+ q = 1
Here, p= frequency of dominant allele
q = frequency of recessive allele
Given, p= 0.8
So, q = 1-p = 1-0.8= 0.2
Frequency of genotype AA = p2 = 0.8 x 0.8 = 0.64 = 64%
Frequency of genotype aa = q2 = 0.2 x 0.2 = 0.04 = 4%
Frequency of genotype Aa = 2pq = 2 x 0.8 x 0.2 = 0.32 = 32%
