The perimeter of the entire figure is 62.8 cm.
Given, that the diameter of the inner semicircles is 9 cm and the width between the outer and inner semicircles is 2 cm.
The radius of the inner semicircle =4.5 cm and the radius of outer semicircle =5.5 cm (∵Diameter=9+2=11 cm)
We need to find the perimeter of the entire figure.
<h3>What is the perimeter?</h3>
A perimeter is a closed path that encompasses, surrounds, or outlines either a two-dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is called its circumference.
We know that, the circumference of a semicircle=πr and the circumference of two semicircles=2πr
Thus, the circumference of inner semicircles=2×3.14×4.5=28.26 cm
The circumference of outer semicircles=2×3.14×5.5=34.54 cm
The perimeter of the entire figure=28.26+34.54=62.8 cm
Therefore, the perimeter of the entire figure is 62.8 cm.
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Answer:
solution = (1.-2)
Step-by-step explanation:
put x= 1 and y = -2 in this system : y=-4x+2 and y + 2x = 0
you have : - 2 = - 4(1)+2 and -2 +2(1)=0
-2=-2 and 0=0 .....right
Answer:
7x²+6x-6
Step-by-step explanation:
1 Combine similar terms
x²+5x+6x²+x-6
7x²+5x+x-6
2 Combine similar terms
7x²+5x+x-6
7x²+6x-6
Answer:
1.8 and 14.3
Step-by-step explanation:
Our equation is a quadratic equation so we will use the dicriminant method
- Let Δ be our dicriminant
- a=1
- b= -16
- c= 25
- Δ= (-16)²-4*25*1=156≥0
- so we have two solutions : x and y
- x= (16-
)/2= 1.7555≈ 1.8 - y=(16+)/2=14.244≈ 14.3
