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gulaghasi [49]
3 years ago
6

In order to maintain a healthy weight, an average adult dog that weighs 20 kilograms must consume 11 grams of dog food per kilog

ram of its body weight each day. A specialty pet store sells dog food by the cup, where 6 cups of dog food weighs 582 grams. About how many cups of dog food should the dog consume each day in order to maintain a healthy weight?
Mathematics
1 answer:
masha68 [24]3 years ago
6 0
2 cups of dog food is 194 grams and 3 cups is 291 grams.
The dog needs 220 grams. So at most 3 cups of dog food. Wish I could simplify more but I can't. sorry.
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billy is creating a circular garden divided into 8 equal sections. The diameter of the garden is 12 feet. what is the area, in s
xxTIMURxx [149]
Area=πr^2

 find the area then divide by 8


we know that diameter=2radius or diameter/2=radius so 
12=diameter
12/2=radius=6
subsitute
area=π(6)^2
area=36π
divide 36π by 8
36π/8=18π/4=9π/2π=4.5π
area of one section is 4.5π square feet or if we aprox pito 3.14159 then we get
4.5(3.14159)=area=14.1372 square feet or 14.14 square feet
5 0
3 years ago
Annalee hammered in nail into a piece of wood each time she hammer the nail it went to 1/8 Inch deeper into the word if she hamm
mash [69]

Answer: 0.5 inch

Step-by-step explanation:

Given

On hammering nail advances \frac{1}{8}\ inch  each time

Annalee hammered 4 times

So, total advancement of nail= 4\times \dfrac{1}{8}=\dfrac{1}{2}\ inch

3 0
3 years ago
△ABC is translated up 5 units to form the image ∆A′B′C′.
otez555 [7]

Answer:

A= -2,4 B=2,4 C= 2,5

Step-by-step explanation:

I tried my best even though C doesn't have a solid answer but A and B are correct so go off that.

6 0
3 years ago
Read 2 more answers
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

3 0
3 years ago
Write a ratio and a percent for the shaded area.
nika2105 [10]
I’m pretty sure it’s 36/100 - 36% since there are 100 boxes and 36 of them are shaded
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