All categories

2 years ago

Find the sum of the first 5,000 odd numbers

Mathematics

1 answer:

Nata [24]2 years ago

4 0

Step-by-step explanation:

this is an arithmetic sequence :

a1 = 1

an = an-1 + 2 = a1 + (n-1)×2

the sum of n terms of an arithmetic sequence is

S = n×(a1 + an)/2

n = 5000

an = a1 + 4999×2 = 9999

S = 5000×(1 + 9999)/2 = 5000×5000 = 25,000,000

You might be interested in

It’s not 3 but still need help with it

Leto [7]

Answer:

Step-by-step explanation:

5-(-8)=13

6 0

3 years ago

Read 2 more answers

What is 10 times 90 divided by -19

Semenov [28]

10 times 90 is 900, and divided by -19 is -900/19.

5 0

3 years ago

Read 2 more answers

What is the slope of a line that is perpendicular to the line shown? (3,3) and (-3,-1)

4vir4ik [10]

Answer:

-3/2

Step-by-step explanation:

Using the slope formula, we can find the slope of the line shown

m = ( y2-y1)/(x2-x1)

= ( -1-3)/(-3-3)

= -4/-6

= 2/3

A line that is perpendicular is the negative reciprocal

-1/ (2/3) = -3/2

8 0

3 years ago

Read 2 more answers

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Suppose you invest $150 a month for 5 years into an account earning 7% compounded monthly. After 5 years, you leave the money, w

lisabon 2012 [21]

Answer:

About 0.3 billion dollars

Step-by-step explanation:

5 years = 60 months.

The 150 of the first month will be 150*1.07^60 in 5 years.

The 150 of the second month will be 150*1.07^59 in 5 years.

The 150 of the third month will be 150*1.07^58 in 5 years.

And so forth.

So we sum that up:

( sum_(n=1)^(60) 150×1.07^n)

And multiply with

× 1.07^(5×23)

to account for the increase in value in the following 23 years.

7 0

3 years ago