You can just plug in one of the points to each equation until you get an equality that is true.
I chose to use (-3,2)
1. 5x+3y=1
5(-3)+3(2)=1
(-15)+ 6 = 1
(-9) = 1 <<<(FALSE)
2. x+5y=3
(-3)+5(2)= 3
(-3)+10= 3
7=3 <<<(FALSE)
3. 3x+5y=1
3(-3) + 5(2)= 1
(-9)+10=1
1=1<<<(TRUE)
So, the correct equation is 3x+5y=1.
Make sense?
As we know that the standard equation of circle is
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
Answer
(a) 
(b) 
Step-by-step explanation:
(a)
δ(t)
where δ(t) = unit impulse function
The Laplace transform of function f(t) is given as:

where a = ∞
=> 
where d(t) = δ(t)
=> 
Integrating, we have:
=> 
Inputting the boundary conditions t = a = ∞, t = 0:

(b) 
The Laplace transform of function f(t) is given as:



Integrating, we have:
![F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.](https://tex.z-dn.net/?f=F%28s%29%20%3D%20%5B%5Cfrac%7B-e%5E%7B-%28s%20%2B%201%29t%7D%7D%20%7Bs%20%2B%201%7D%20-%20%5Cfrac%7B4e%5E%7B-%28s%20%2B%204%29%7D%7D%7Bs%20%2B%204%7D%20-%20%5Cfrac%7B%283%28s%20%2B%201%29t%20%2B%201%29e%5E%7B-3%28s%20%2B%201%29t%7D%29%7D%7B9%28s%20%2B%201%29%5E2%7D%5D%20%5Cleft%20%5C%7B%20%7B%7Ba%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
Inputting the boundary condition, t = a = ∞, t = 0:

Answer:
A.-2x2+-1
Step-by-step explanation:
(-7x+5)-(2x2-8x+6)
-7x+5-2x2+8x-6 then collect like terms
-2x2-7x+8x+5-6
-2x2-x+1
If it's helpful ❤❤❤
THANK YOU
Answer:
~48$
Step-by-step explanation:
0.47/25=0.0188
0.0188×211=3.9
12 cause of 9am to pm
12×3.9=47$