Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
10(6) + 25 = 60 + 25 = 85
10(2.75) + 25 = 27.5 + 25 = 52.5
10(1.482) + 25 = 14.82 + 25 = 39.82
93 = 10x + 25 || 68 = 10x || x = 6.8
42.1 = 10x + 25 || 17.1 = 10x || x = 1.71
116.25 = 10x + 25 || 91.25 = 10x || x = 9.125
Answer:
$8.4375 per game
Step-by-step explanation:
From. The picture attached :
Season long Ticket cost for the bleachers sitting area is : $810
Given that the number of home games in a season is 96
The cost per unit of game could be calculated as :
Cost of season long Ticket / number of home games
= $810 / 96
= $8.4375
$8.4375 per game
