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ycow [4]
2 years ago
10

Mrs. Booker was being chased by a horde of zombies. She had to run 8 yards to make it to a safe zone. How far did she run in fee

t?
Mathematics
1 answer:
Vikentia [17]2 years ago
5 0

Answer:

24 feet

Step-by-step explanation:

Given that,

Mrs. Booker had to run 8 yards to make it to a safe zone.

We need to convert this distance in feet.

The conversion from yards to feet is as follows :

1 yard = 3 feet

So,

8 yards = 24 feet

Hence, Mrs. Booker had to run 24 feet to make it to a safe zone.

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Can someone please help me with all of these problems. They are a ton of them and they are due tomorrow. PLEASE AND THANK YOU
Masteriza [31]

15. \frac{x}{5} - g = a

Add "g" on both sides

\frac{x}{5}  = a +g

Multiply 5 on both sides to get x by itself

x = 5(a + g)

x = 5a + 5g


18. a = 3n + 1

Subtract 1 on both sides

a - 1 = 3n

Divide 3 on both sides to get n by itself

\frac{a - 1}{3}  = \frac{a}{3} -\frac{1}{3} = n


21. M = T - R

Add "R" on both sides to get "T" by itself

M + R = T


24. 5p + 9c = p

Subtract "5p" on both sides

9c = p - 5p

9c = -4p

Divide 9 on both sides to get "c" by itself

c = \frac{-4p}{9} or c = \frac{-4}{9} p


27. 4y + 3x = 5

Subtract "4y" on both sides

3x = 5 - 4y

Divide 3 on both sides to get "x" by itself

x = \frac{5-4y}{3}

x = \frac{5}{3} -\frac{4y}{3}

7 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
2 years ago
A circle has an area of 40 square inches. Find the radius to 2 decimal places.
Oksanka [162]

The area of a circle is given by

A=\pi r^2

We can solve this equation for r: divide both sides by pi:

r^2=\dfrac{A}{\pi}

Consider the (positive) square root of both sides:

r = \sqrt{\dfrac{A}{\pi}}

So, in your case, we have

r = \sqrt{\dfrac{40}{\pi}}\approx 3.57

7 0
3 years ago
Jan walked 1/2 mile in 1/3 hours. at this rate, how far will she walk in one hour?
Oxana [17]
I hope this helps you

6 0
3 years ago
What is m∠A ?<br><br><br><br><br><br> Enter your answer in the box.<br><br> °
slava [35]
The definition of the interior angles of a triangle states that interior angles of a triangle add up to 180º.

This means we can find the measure of <CED: 

<CED + <ECD + <CDE = 180º
<CED = 180º - <ECD - <CDE
<CED = 180º - 43º - 35º
<CED = 102º

By the definition of vertical angles states that a pair of vertical angles are congruent.

This means <CED = <AEB
If <CED = 102º 
Then <AEB = 102º

By definition of the interior angles of triangles:
<AEB + <EBA + <BAE = 180º

<AEB = 102º
<EBA = 18º

102º + 18º + <BAE(<A) = 180º

<BAE = 180º - 102º - 18º
<BAE = 60º

<BAE is another way to say <A

<span>m∠A  = 60º</span>




5 0
3 years ago
Read 2 more answers
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