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Tomtit [17]
3 years ago
5

Evaluate 1/3 divided by 1/2

Mathematics
2 answers:
scoray [572]3 years ago
7 0

Answer:

   2/3

Step-by-step explanation:

so what you do is switch the numerators and deno. (1/3 1/2)turns into 3/1 and 2/1 you multiple both top and bottom numbers and boom!!

(simplify if need)

svp [43]3 years ago
3 0

Answer:

2/3

Step-by-step explanation:

1/3 x 2/1 = 2/3

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A new fitness center opens with 120 members. Every month the fitness center increases the number of members by 40 members. How m
soldier1979 [14.2K]

Answer:

<u>240 members</u>

Step-by-step explanation:

Let y = total and x = no. of months

y = 40x + 120

= 40(3) + 120

= 120 + 120

= <u>240 members</u>

4 0
2 years ago
The ordered pair (-2,-1) is a solution to which of the following equations?
saveliy_v [14]

Answer:

5x-2y=12

Step-by-step explanation:

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2 years ago
Write an expression in simplest form to represent the area of the shaded region <br> 3x+2 2x 3x 4x
Taya2010 [7]
12x+2

explication:
2x+3x= 5x
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8 0
3 years ago
stevie has 1/4 of a gallon of paint. he divided the paint equally into 3 containers. How much paint did he put in each container
Ket [755]

Answer:

  1/12 gallon

Step-by-step explanation:

Each container got 1/3 of the original amount, so ...

  (1/3)(1/4 gal) = 1/12 gal

Stevie put 1/12 gallon of paint in each container.

7 0
3 years ago
Can u help solve these questions please
Tasya [4]

Answer:

Step-by-step explanation:

\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}} [Since, \sqrt[n]{x}=x^{\frac{1}{n}}]

               =(16)^{\frac{5}{4}}(a^4)^{\frac{5}{4}}

               =(2^4)^{\frac{5}{4}}(a^4)^{\frac{5}{4} }

               =(2^{4\times \frac{5}{4}})(a^{4\times \frac{5}{4}})

               =2^5a^5

\sqrt[5]{(b^{\frac{1}{4}})^6}=\sqrt[5]{b^{\frac{6}{4}}}

           =\sqrt[5]{b^{\frac{3}{2}}}

           =(b^{\frac{3}{2}})^{\frac{1}{5} }

           =b^{\frac{3}{10}}

\sqrt[3]{\frac{c^{15}}{c^9}}=\sqrt[3]{c^{15-9}}

         =(c^6)^{\frac{1}{3}}

         =c^{6\times \frac{1}{3} }

         = c²

\sqrt[4]{16d^6\times 16d^{-5}}=\sqrt[4]{(2)^4(d^{6-5})(2)^4}

                        =\sqrt[4]{2^{(4+4)}d}

                        =\sqrt[4]{(2^8)d}

                        =2^{\frac{8}{4}}d^{\frac{1}{4}}

                        =2^2d^{\frac{1}{4}}

                        =4d^{\frac{1}{4}}

8 0
3 years ago
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