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-Dominant- [34]
2 years ago
15

Solve please 14a⁹b-8a³d÷ 2a³​

Mathematics
1 answer:
koban [17]2 years ago
7 0

Answer:

7a^6b-4d

Step-by-step explanation:

\frac{14a^9b - 8a^3d}{2a^3} \\\frac{2a^3(7a^6b - 4d)}{2a^3} \\\\7a^6b-4d

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A square piece of cheese covers 10 square inches of a plate. What is the approximate length of one side of the piece of cheese?
Airida [17]

Answer:

3.16 inches

Step-by-step explanation:

Sqrt 10 = 3.16 inches

3 0
2 years ago
Read 2 more answers
Divide fractions 1/2 divided by 1/6
SVEN [57.7K]
1/2 divided by 1/6 is 3

use KCF strategy

1/2 x 6/1=3

1x6=6

2x1=2

6/2=3
4 0
3 years ago
What is the answer to 10lb 6oz- 7lb 11oz
sweet-ann [11.9K]
1 lb = 16 oz
Translating the unit into oz gives us
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3 0
2 years ago
Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5
Marianna [84]
\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}

\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)

of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
7 0
3 years ago
I NEED HELP ASAP. PLEASE TELL ME WHERE I WOULD GRAPH AND WHERE I WOULD SHADE. ALSO IF THE LINE WOULD BE SOLID OR NOT. 20 POINTS
luda_lava [24]

The first one is a dashed line and the second one is solid. Two points for the first one is (1,4) and (0,3). For the second one two points are (0,-3) and (1,0). From build the lines. Finally the first one is where y is greater so shade above the line with points like ( 10,10) or (7,8) in the shaded region. For the second one since y is less or equal to shade below the line with points like (-2,-10) or (-1,-5).

3 0
2 years ago
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