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Kazeer [188]
3 years ago
9

there are four children in Jana's family. She is less than 11 years old and is the oldest. there's a two-years age difference to

twins, riya and seta, who come next. yuvi who is older than 5 is 2 years younger than the twins. how old are each of the children?​
Mathematics
1 answer:
icang [17]3 years ago
8 0

Answer:

Jana=10, twins=8, yuvi=6

Step-by-step explanation:

it's the only possible answer,as we know yuvi is older than 5 so let's just say she is 6 then the twins are 2 years older=8 and we know that and is less then 11 so that would be 10

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7 1/4 × 2²+(8 1/2-2)÷3<br>giving brainliest
lawyer [7]

Answer:

187/6

Step-by-step explanation:

Simplify the following:

(7 + 1/4) 2^2 + (8 + 1/2 - 2)/3

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(7 + 1/4) 4 + (8 + 1/2 - 2)/3

Put 7 + 1/4 over the common denominator 4. 7 + 1/4 = (4×7)/4 + 1/4:

(4×7)/4 + 1/4 4 + (8 + 1/2 - 2)/3

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(28/4 + 1/4) 4 + (8 + 1/2 - 2)/3

28/4 + 1/4 = (28 + 1)/4:

(28 + 1)/4×4 + (8 + 1/2 - 2)/3

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(29×4)/4 + (8 + 1/2 - 2)/3

(29×4)/4 = 4/4×29 = 29:

29 + (8 + 1/2 - 2)/3

Put 8 + 1/2 - 2 over the common denominator 2. 8 + 1/2 - 2 = (2×8)/2 + 1/2 + (2 (-2))/2:

29 + ((2×8)/2 + 1/2 + (2 (-2))/2)/3

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29 + (16/2 + 1/2 + (2 (-2))/2)/3

2 (-2) = -4:

29 + (16/2 + 1/2 + (-4)/2)/3

16/2 + 1/2 - 4/2 = (16 + 1 - 4)/2:

29 + ((16 + 1 - 4)/2)/3

16 + 1 = 17:

29 + ((17 - 4)/2)/3

| 1 | 7

- | | 4

| 1 | 3:

29 + (13/2)/3

13/2×1/3 = 13/(2×3):

29 + 13/(2×3)

2×3 = 6:

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(6×29)/6 + 13/6

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174/6 + 13/6

174/6 + 13/6 = (174 + 13)/6:

(174 + 13)/6

| 1 | 7 | 4

+ | | 1 | 3

| 1 | 8 | 7:

Answer: 187/6

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Answer:

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