Algebra 1 is a high school course. You learn some of the same things but in algebra it's more complicated.
The answer is 0 < x <span>≤ 7
</span>
First, we know that width = x
Which means that length = x +18
So, the possible equation for the Table's area is
X (X + 18) ≤ 175
X^2 + 18x - 175 <span>≤ </span>0
Next, we need to calculate is by using complete square method
x^2 + 18x + 81 <span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
Since the width couldn't be negative, we can change -25 with 0,
so it become
</span> 0 < x ≤ 7
Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:
<em>f(x) = 2(x - 3)^2 - 2</em>
<em></em>
Domain: (-∞, ∞)
Range: (-2, ∞)
X-intercepts: (4, 0), (2, 0)
Y-intercept: (0, 16)
Axis of Symmetry: x = 3
Minimum value (vertex): (3, -2)
Standard form: y = 2x^2 - 12x + 16
Answer:
4-13=-9
Step-by-step explanation:
