Ask question

Ask question

All categories

2 years ago

13

According to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches, with a standard

deviation of 0.07 inches. What is the probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days (taken over many years)?
Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

1 answer:

Andru [333]2 years ago

8 0

Answer:

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 0.10 inches

Given that the standard deviation of the population = 0.07inches

Let 'X' be a random variable in a normal distribution

$Z = \frac{x-mean}{S.D} = \frac{0.11-0.10}{0.07} = 0.1428$

<u><em>Step(ii):-</em></u>

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = P(Z≤0.1428)

= 1-P(Z≥0.1428)

= 1 - ( 0.5 +A(0.1428)

= 0.5 - A(0.1428)

= 0.5 -0.0596

= 0.4404

<u><em>Final answer:-</em></u>

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

You might be interested in

What is the sum of (2x4 + 5x3 - 8x2 - x + 10) and (8x4 - 4x3 + x2 - x + 2)?

balu736 [363]

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Step-by-step explanation:

Given polynomials are:

$P_1 : 2x^4+5x^3-8x^2-x+10\\P_2: 8x^4-4x^3+x^2-x+2$

We have to find the sum of polynomials

So,

$S = P_1+P_2\\= (2x^4+5x^3-8x^2-x+10) + (8x^4-4x^3+x^2-x+2)\\=2x^4+5x^3-8x^2-x+10+8x^4-4x^3+x^2-x+2\\$

Combining like terms

$=2x^2+8x^4+5x^2-4x^3-8x^2+x^2-x-x+10+2\\= 10x^4+x^3-7x^2-2x+12$

Hence,

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Keywords: Polynomials, sum

Learn more about polynomials at:

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

Which of the relations given by the following sets of ordered pairs is a function?

adell [148]

Functions cannot have the same X value (the first number), but they can have the same Y value (the second number).
<span>A. {(1,2),(2,3),(3,4),(2,1),(1,0)}
B. {(2,−8),(6,4),(−3,9),(2,0),(−5,3)}
C. {(1,−3),(1,−1),(1,1),(1,3),(1,5)}
D. {(−2,5),(7,5),(−4,0),(3,1),(0,−6)}

Choice A. has two repeating X values [(1,2) and (1,0), (2,3) and (2,1)]
Choice B. has one repeating X value [(2, -8) and (2,0)]
Choice C. all has a repeating X value (1)
Choice D doesn't have any repeating X values.

In short, your answer would be choice D [</span><span>{(−2,5),(7,5),(−4,0),(3,1),(0,−6)}] because it does not have any repeating X values.</span>

8 0

3 years ago

Tell me the answer to the question plz

Sonja [21]

Step-by-step explanation:

(11.99+23.98+9.95)= 45.92

she has to pay = 45.92 - 20/100 (45.92)

= 45.92 - 9.18 = 36.74

so option

about 37 is right

4 0

3 years ago

What is the cost of gas at 4.6 $2.70 per gallon

Anarel [89]

Answer:

$12.42

Step-by-step explanation:

4.6 gallons at 2.70 per gallon.

4.6*2.70= $12.42

3 0

3 years ago

Help me solve this please

shutvik [7]

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = $\sqrt{(-28-3.5)^2+(-17.5-24.5)^2}$

= $\sqrt{(-31.5)^2+42^2}$

= $\sqrt{992.25+1764}$

= $\sqrt{2756.25}$

= 52.5 units

7 0

2 years ago