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kumpel [21]
3 years ago
11

When the volume of the gas is 16 cm3, its pressure is 20 L/cm2. Find the volume of the gas when the pressure is 2.2 L/cm2.

Mathematics
2 answers:
olga55 [171]3 years ago
6 0
The answer is a.145.45cm^3

gizmo_the_mogwai [7]3 years ago
6 0

Answer:

option A

Step-by-step explanation:

given,

Volume of gas(V₁) = 16 cm³

Pressure of the gas(P₁) = 20 L/cm²

Volume of Gas(V₂) when pressure(P₂) is 2.2 L/cm²

considering temperature constant

                             P₁ V₁ = P₂ V₂

                             20 × 16  =2.2 × V₂

                               V₂ =\dfrac{20\times 16}{2.2}

                               V₂ = 145.45 cm³

hence, the correct answer is option A

                   

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The explicit formula for the geometric sequence 10,30,90,180
alukav5142 [94]

Answer:

a_{n} = 10 (3)^{n-1}

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a (r)^{n-1}

where a is the first term and r the common ratio

Here a = 10 and r = 30 ÷ 10 = 3, thus

a_{n} = 10 (3)^{n-1}

7 0
3 years ago
Read 2 more answers
9. The figure shows a rectangle with its length and
lora16 [44]

Answer:

875cm^2

Step-by-step explanation:

since opposite sides are equal

3x-y=2x+y

x=2y                                                      

y=x/2                                                                      ....(i)

thus new length=2x+y

=2x+(x/2)                                                              [using (i)]

=(4x+x)/2

l=5x/2                                                                   .....(ii)

now,

perimeter=2(l+b)=120cm

l+b=60cm            

from figure and using (ii)

[5x/2]+2x-3=60

[5x+4x-6]/2=60

9x-6=120

9x=126

x=126/9

x=14                                                                 ..........(iii)

substitute (iii) in (i)

y=14/2

y=7                                                                  ...........(iv)

From figure,

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=2x14+7

length=35cm

breadth=2x-3

=2x14-3                                                          ....[using(iii)]

=28-3

breadth=25cm

now,

Area=lxb

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=875cm^2

7 0
3 years ago
An electronics company makes communication devices for military contracts. The company just completed two contracts. The navy co
adelina 88 [10]

Answer:

Workers of army contract were more productive.

Step-by-step explanation:

To determine on which contract the workers were more productive compute the work done per hour by the workers for both contracts.

  • <u>Navy Contract</u>:

Number of devices = 2,300

Number of workers = 25

Number of weeks = 2 weeks

Number of hours per week = 40

The number of hours it took 25 workers to produce 2300 devices is =

=25\times2\times40\\=2000\ hours

Then number of devices produced in 1 hour is = \frac{2300}{2000}= 1.15\ devices\ per\ hour

  • <u>Army Contract</u>:

Number of devices = 5,500

Number of workers = 35

Number of weeks = 3 weeks

Number of hours per week = 40

The number of hours it took 35 workers to produce 5500 devices is ==35\times3\times40\\=4200\ hours

Then number of devices produced in 1 hour is = \frac{5500}{4200}= 1.31\ devices\ per\ hour

The workers for the army contract are more productive since they produce 1.31 devices per hour whereas the workers for navy contract produces 1.15 devices per hour.

4 0
3 years ago
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SashulF [63]

Answer:

B, \sqrt 156

Step-by-step explanation:

B \sqrt156 = 12.489996

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D\sqrt196=14

3 0
3 years ago
Can some one explain how to do this?
Delvig [45]

Answer:

see explanation

Step-by-step explanation:

Using the tangent and sine ratios in the right triangle EFG

tan60° = \frac{opposite}{adjacent} = \frac{FG}{EG} = \frac{28}{EG} ( multiply both sides by EG )

EG × tan60° = 28 ( divide both sides by tan60° )

EG = \frac{28}{tan60} ≈ 16.2 in ( to the nearest tenth )

--------------------------------------------------------------

sin60° = \frac{opposite}{hypotenuse} = \frac{FG}{EF} = \frac{28}{EF} ( multiply both sides by EF )

EF × sin60° = 28 ( divide both sides by sin60° )

EF = \frac{28}{sin60} ≈ 32.3 in ( to the nearest tenth )

3 0
3 years ago
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