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sesenic [268]
3 years ago
13

PLEASE HELP!

Mathematics
1 answer:
solong [7]3 years ago
3 0

Answer:

x = -1

y = -2

Step-by-step explanation:

here's the solution in attached image .

Answer : second problem .

=》x = 8

=》y = 8

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Use trianglePQR to write the trigonometric ratio as a decimal. round to four decimal places.
astraxan [27]
I hope this answer helps, it’s kinda messy, but it’s still understandable (I guess)

4 0
3 years ago
Is 13/ 4 the same as 3 1/4 ? Explain your answer in complete sentences. ​
Andrew [12]

Answer:

no it is not the same.

Step-by-step explanation:

it is not the same because 13/4 is smaller than 3/14. 3 1/4 includes a whole number, and 13/4 doesn't.

4 0
3 years ago
Plzzzz help me on this
Grace [21]
Answer: 228 feet squared

How: To get the area of the entire field, multiply 25•36 to get 900. To find length of the area inside the path, you have to subtract 2 feet from both sides of 25, which is also 4 feet, to get 25-4=21. To find the width of the area inside the path, you have to subtract 2 feet from both sides of 36, which is also 4 feet, to get 36-4=32. You multiply 21•32 to get 672, which is the area of the field inside of the path. To find the area of the path, you subtract the total area of the field and the path together, which is 900, by 672 to get 228 feet squared.
7 0
3 years ago
Read 2 more answers
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

6 0
3 years ago
I NEED HELP
4vir4ik [10]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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