Suppose that alpha and beta are int variables. The statement alpha = beta--; is equivalent to the statement(s) ____.

1 answer:

5 0

D. The unary postfix decrement operator, when used in an expression, decrements the value of its operand but has the old value of the operand.

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what is the degree of the polynomial ? what is the leading coefficient ? describe the end behavior of each function. f(x)=x^4-2x

Verizon [17]

Answer:

4th degree polynomial with leading coefficient of 1.

As x goes to negative or positive infinity, y goes to positive infinity in both cases.

Step-by-step explanation:

The degree of a polynomial is the highest exponent on the variable. Here it is 4.

The leading coefficient is the coefficient on the the term with the highest degree, Here there is none so it is 1.

The end behavior is how x and y behave at negative and positive infinity. When graphed, this equation has a W shape. This means at each end y goes to positive infinity.

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4 years ago

HELP ME ANSWER THIS PLEASE!!!!! Complete the proof that m

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3 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

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3 years ago

Gloria collected data from a random sample of 1200 students in her school district asking whether or not they read more than one

Vitek1552 [10]

Answer: Sample is biased

Step-by-step explanation:

In her experiment, Gloria assumes that the reading habits of the students in her school district are exactly the same to that of students in all state schools. This assumption is unlikely to be true and, therefore, this statistic is misleading because the sample used is biased.

From her data, all Gloria can do is report the percentage of students that read more than one book per month in her school district

Step-by-step explanation:

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4 years ago

Given PQ = 24

Verdich [7]

The shape PQRS is a parallelogram