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3 years ago

13

HEEEEEEEELP ASAP 30 POINTS!!!!!!!!!!!

2 answers:

olchik [2.2K]3 years ago

7 0

Answer:

it's the first one i took the test

Step-by-step explanation:

otez555 [7]3 years ago

6 0

I think its the first one

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If there is 360 grams of radioactive material with a half-life of 8 hours, how much of the radioactive material will be left aft

AnnZ [28]

22.5 grams : Exponential

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3 years ago

Simplify the rational expression. State any restrictions on the variable. t^2-4t-32/t-8

Leno4ka [110]

1. Factor the expression $t^2-4t-32:$

$t^2-4t-32=(t-8)(t+4).$

2. Since $t-8$ is placed in the denominator of the given expression, then $t\neq 8.$

3. Now the expression can be simplified:

$\dfrac{t^2-4t-32}{t-8}=\dfrac{(t-8)(t+4)}{t-8}=t+4.$

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3 years ago

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Tell whether x and y are in a proportional relationship. Explain<br> your reasoning.

notsponge [240]

No because they 90 to 200 is 110 but 200 to 325 is 125

110 obviously does not equal 125

8 0

3 years ago

Please help! I will not need help with the graph at the bottom just the equation

gladu [14]

isolate y

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4y=-2x-8

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y=-1/2x-2

6 0

3 years ago

Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri

Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after $\frac{640}{7}$ miles

Step-by-step explanation:

Given

The table represents the car mileage

$y = -\frac{1}{5}x + 31$ --- The van

First, calculate the car's slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

From the table, we have:

$(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)$

So, we have:

$m = \frac{10.5 - 13.5}{180 - 60}$

$m = \frac{-3}{120}$

$m = -\frac{1}{40}$

Calculate the equation using:

$y = -\frac{1}{40}(x - 60)+13.5$

$y = -\frac{1}{40}x + 1.5+13.5$

$y = -\frac{1}{40}x + 15$

$m = -\frac{1}{40}$ implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

$y = -\frac{1}{5}x + 31$ --- The van

By comparison to: $y = mx + b$

$m = -\frac{1}{5}$

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

$1/40 < 1/5$

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

$y = -\frac{1}{5}x + 31$ --- The van

$y = -\frac{1}{40}x + 15$ --- The car

Equate both

$-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15$

Collect like terms

$\frac{1}{40}x -\frac{1}{5}x =-31 + 15$

$\frac{1}{40}x -\frac{1}{5}x =-16$

Take LCM

$\frac{x - 8x}{40} = -16$

$\frac{- 7x}{40} = -16$

Solve for -7x

$-7x = -640$

Solve for x

$x = \frac{640}{7}$

5 0

3 years ago