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zmey [24]
3 years ago
13

HEEEEEEEELP ASAP 30 POINTS!!!!!!!!!!!

Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0

Answer:

it's the first one i took the test

Step-by-step explanation:

otez555 [7]3 years ago
6 0
I think its the first one

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If there is 360 grams of radioactive material with a half-life of 8 hours, how much of the radioactive material will be left aft
AnnZ [28]
22.5 grams : Exponential

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3 years ago
Simplify the rational expression. State any restrictions on the variable. t^2-4t-32/t-8
Leno4ka [110]

1. Factor the expression t^2-4t-32:

t^2-4t-32=(t-8)(t+4).

2. Since t-8 is placed in the denominator of the given expression, then t\neq 8.

3. Now the expression can be simplified:

\dfrac{t^2-4t-32}{t-8}=\dfrac{(t-8)(t+4)}{t-8}=t+4.

5 0
3 years ago
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Tell whether x and y are in a proportional relationship. Explain<br> your reasoning.
notsponge [240]
No because they 90 to 200 is 110 but 200 to 325 is 125

110 obviously does not equal 125
8 0
3 years ago
Please help! I will not need help with the graph at the bottom just the equation
gladu [14]

isolate y

move y to the right

4y=-2x-8

divide by 4

y = -1/2x -2

solution is

y=-1/2x-2

6 0
3 years ago
Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri
Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after \frac{640}{7} miles

Step-by-step explanation:

Given

The table represents the car mileage

y = -\frac{1}{5}x + 31 --- The van

First, calculate the car's slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)

So, we have:

m = \frac{10.5 - 13.5}{180 - 60}

m = \frac{-3}{120}

m = -\frac{1}{40}

Calculate the equation using:

y = -\frac{1}{40}(x - 60)+13.5

y = -\frac{1}{40}x + 1.5+13.5

y = -\frac{1}{40}x + 15

m = -\frac{1}{40} implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

y = -\frac{1}{5}x + 31 --- The van

By comparison to: y = mx + b

m = -\frac{1}{5}

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

1/40 < 1/5

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

y = -\frac{1}{5}x + 31 --- The van

y = -\frac{1}{40}x + 15 --- The car

Equate both

-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15

Collect like terms

\frac{1}{40}x -\frac{1}{5}x  =-31 + 15

\frac{1}{40}x -\frac{1}{5}x  =-16

Take LCM

\frac{x - 8x}{40} = -16

\frac{- 7x}{40} = -16

Solve for -7x

-7x = -640

Solve for x

x = \frac{640}{7}

5 0
3 years ago
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