All categories

4 years ago

What do i do? What do they mean ...HELP ME!!

Mathematics

1 answer:

katrin2010 [14]4 years ago

4 0

Sin x = a/c

cos x b/c

tan x = a/b

You might be interested in

5. Consider the diagram below. Solve for x.

Svetradugi [14.3K]

I believe that x is 35.

I hope this helps!

8 0

3 years ago

Read 2 more answers

Can someone please help me

defon

9514 1404 393

Answer:

P = 50,000

r = 0.08

i = 0.02

K = 4

n = 20

t = 5

Step-by-step explanation:

In this formula, r is the annual interest rate, 8% or 0.08. K is the number of times the interest is compounded in a year. Since interest is compounded quarterly, K = 4.

r = 0.08

i = r/K = 0.08/4

i = 0.02

t is the number of years interest is compounded, so ...

t = 5

n = Kt = 4·5

n = 20

P is the principal amount invested:

P = 50,000

7 0

3 years ago

Brilliant_brown [7]

Answer:

4^5x-1=16

4^5x-1=4²eliminate 4

5x-1=2

5x=2+1

5x=3

x=3/5

log4(10x+2)=1

log4(10x+2)=log4 ⁴

eliminate log4

10x+2=4

10x=4-2

10x=2

x=2/10

x=1/5

difference between the is we use law of indices and logarithm to the questions respectively

similarities is we eliminate there base

8 0

2 years ago

Simplify 3^6.3. O A. 3^7 O B. 3^5 O c. 3^6 O D. 9^6 ASSSAPPP!!!!!!!!!!

Lapatulllka [165]

Answer:

D. $9^{6}$

Step-by-step explanation:

(3^6)(3)

(3*3)^6

$9^{6}$

3 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago