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Mathematics

1 answer:

katrin2010 [14]3 years ago

4 0

Sin x = a/c

cos x b/c

tan x = a/b

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What’s 1/6 plus 3/8 in simplest form

gregori [183]

13/24 is the answer to your problem.

7 0

3 years ago

What is the answer to this math problem??

lakkis [162]

Answer:

Step-by-step explanation:

given $\frac{1}{49^2}$

note that 49² = 2401, hence

$\frac{1}{49^2}$ = $\frac{1}{2401}$ → A

4 0

2 years ago

Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.

WARRIOR [948]

The polynomial $2x^3 + 5x^2-8x-20$ may have solutions which are the divisors of -20, therefore -20 has the following divisors: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .
If x=1, then $2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0$ ,
if x=-1, then $2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0$ ,
if x=2, then $2\cdot2^3 + 5\cdot2^2-8\cdot2-20=0$ , then x=2 is a solution and you have the first factor (x-2).
If x=-2, then $2\cdot(-2)^3 + 5\cdot(-2)^2-8\cdot(-2)-20=0$ , then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of $2x^3 + 5x^2-8x-20$ , then the polynomial $x^2-4$ is a divisor of $2x^3 + 5x^2-8x-20$ and dividing the polynomial $2x^3 + 5x^2-8x-20$ by $x^2-4$ you obtain
$2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5)$ .

5 0

2 years ago

Read 2 more answers

What is 6 to the negitive 3rd power?

almond37 [142]

Get rid of negative exponents by remembering that x^-a= 1/x^a.

6^-3= 1/6^3

Evaluate the exponent
6^3= 216

Final answer: 1/216

5 0

2 years ago

What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y=13 x−1 ?

nadezda [96]

10=13(6)+b
10=78+b
b=-68
y=13x-68

7 0

2 years ago