Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC;           in triangle ΔFGH;
              in triangle ΔFGH; 
Segment  = 14
 = 14          Segment
               Segment  = 14
 = 14
Segment  = 27
 = 27          Segment
              Segment  = 19
 = 19
Segment  = 19
 = 19          Segment
               Segment  = 2·y + 5
 = 2·y + 5
∡A = 32°                        ∡G = 32°
                ∡G = 32°
∡A = ∠BAC which is the angle formed by segments  = 14 and
 = 14 and  = 19
 = 19 
Therefore, segment  = 27, is the segment opposite to ∡A = 32°
 = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments  = 14 and
 = 14 and  = 19
 = 19
Therefore, segment  = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
 = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
 ≅
 ≅  by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
 by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴  =
 =  = 27° y definition of congruency
 = 27° y definition of congruency
 = 2·y + 5 = 27° by transitive property
 = 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27° 
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°