Answer:
a) 28,662 cm² max error
0,0111 relative error
b) 102,692 cm³ max error
0,004 relative error
Step-by-step explanation:
Length of cicumference is: 90 cm
L = 2*π*r
Applying differentiation on both sides f the equation
dL = 2*π* dr ⇒ dr = 0,5 / 2*π
dr = 1/4π
The equation for the volume of the sphere is
V(s) = 4/3*π*r³ and for the surface area is
S(s) = 4*π*r²
Differentiating
a) dS(s) = 4*2*π*r* dr ⇒ where 2*π*r = L = 90
Then
dS(s) = 4*90 (1/4*π)
dS(s) = 28.662 cm² ( Maximum error since dr = (1/4π) is maximum error
For relative error
DS´(s) = (90/π) / 4*π*r²
DS´(s) = 90 / 4*π*(L/2*π)² ⇒ DS(s) = 2 /180
DS´(s) = 0,0111 cm²
b) V(s) = 4/3*π*r³
Differentiating we get:
DV(s) = 4*π*r² dr
Maximum error
DV(s) = 4*π*r² ( 1/ 4*π*) ⇒ DV(s) = (90)² / 8*π²
DV(s) = 102,692 cm³ max error
Relative error
DV´(v) = (90)² / 8*π²/ 4/3*π*r³
DV´(v) = 1/240
DV´(v) = 0,004
Answer:
10
Step-by-step explanation:
2*3=6
6+c
6+4=10
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So, all percents can be expressed as *percent*/100
So for this, it would be 150/100
Then we want to simplify it down and all that jazz. Find the biggest number that BOTH the numerator AND denominator can be divided by.
In this case, 50.
150/50=3
100/50=2
So now you have 3/2
You might also want a mixed number, or, a whole number with the leftover fraction after it.
In this case, see how many times can 2 go into 3 FULLY.
The answer would be 1. 1 is our WHOLE NUMBER.
Then take whatever is left over from 3 and that is our numerator. Do this, since 2 can go into 3 ONE time FULLY, I can say 3-(2*1) is our remainder.
That gives you one as the numerator. 2 is still the denominator.
So a mixed number of 3/2 is 1 1/2
So here is 150% as a fraction: 150/100, 3/2 or 1 1/2.
I hope I helped!!! -Kibeye/Ethan
Answer: 10,883.6
Step-by-step explanation: So first we have to find out what the depreciation is and to find that we have to take the 20,930 and times it by 0.06 (6%) which is 1,255.8,
So, we then times 1,255.8 by 8 because 8 years of depreciation, which is 10,046.4,
Finally we take 20,930 (the cars total value) and subtract the depreciation from it (10,046.4) so in 8 years the car is worth 10,883.6
If you need any further instruction or help let me know!
