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Naily [24]
2 years ago
6

Given the data, as shown in the image below, determine if the distribution is uniformly distributed, symmetrically distributed,

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
4 0

Answer:A

Step-by-step explanation:

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0.63 =<br> How do you convert this into a fraction
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Step-by-step explanation:

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m = 15

Step-by-step explanation:

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m = 21 - 6

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m=15

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
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