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Sladkaya [172]
3 years ago
7

Tasha invests $5000 annually at 6% and an additional $5000 annually at 8%. Thomas invests $10000 annually at 7%. Which statement

accurately compares the two investments if interest is compounded annually
Mathematics
2 answers:
REY [17]3 years ago
6 0

Answer:

Answer:

Option B is correct.

Step-by-step explanation:

We will compare the interest earned by both.

Tasha: p = $5000

r = 6% or 0.06

n = 1

So, Amount after a year will be = = $5300

And amount the next year with p = 5300: 5300*1.06= $5618

Additional $5000 at 8%

Here the amount will be = =5400

Next year amount with p = 5400 : 5400*1.08 = $ 5832

Amount in total Tasha will have in 2 years = 5618+5832 = 11450

Thomas:

p = 10000

r = 7% or 0.07

n = 1

After a year the amount will be = =$10700

Amount Next year with p = 10700 : 10700*1.07 = $11449

*****Just after 1 year we can see that Tasha's total amount is high than Thomas. This means at the same consistent rate, each year Tasha's amount will always be higher than Thomas.

So, option B is correct. Tasha’s investment will yield more over many years because the amount invested at 8% causes the overall total to increase faster.

stira [4]3 years ago
5 0

Answer:

B) Tasha’s investment will yield more over many years because the amount invested at 8% causes the overall total to increase faster.

Step-by-step explanation:

I just took the test on edge

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What is -3/4 + 3/8? Thanks.
AURORKA [14]

Answer:

-  \frac{3}{8}

Step-by-step explanation:

First, we change both denominators to the LCM (lowest common multiple) which is 8.

-  \frac{3}{4}  +  \frac{3}{8}  =  -  \frac{6}{8}  +  \frac{3}{8}

Since the denominators are the same, we can add the numerators.

\frac{ - 6 + 3}{8}

\frac{ - 3}{8}

or it can be written as

-  \frac{3}{8}

7 0
3 years ago
Read 2 more answers
What is the solution to the equation
Dafna11 [192]
\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6

therefore
D:x\in\left< -\dfrac{5}{4};\ 6\right>

\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs
9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D
Answer: t = -1.


7 0
3 years ago
Read 2 more answers
Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

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3 0
3 years ago
Sum of 2 numbers is 42, and their difference is 8. What are the numbers?​
Tems11 [23]

Answer:

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Step-by-step explanation:

Let the unknown two numbers be x & y.

According to the question,

Sum of 2 numbers is 42.

x + y = 42  ⇒ ( 1 )

Their difference is 8.

x - y = 8 ⇒ ( 2 )

First let us find the value of x.

( 1 ) + ( 2 )

x + y + x - y = 42 + 8

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Divide both sides by 2.

x = 25

And now let us find the value of y.

x + y = 42

25 + y = 42

y = 42 - 25

y = 17

Therefore, the two numbers are 25 , 17

Hope this helps you :-)

Let me know if you have any other questions :-)

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Radda [10]

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6 0
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