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Nookie1986 [14]
3 years ago
14

A group of 300 students were divided into small groups based on their year of birth.

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer:

Students born in 2000= 300*(1/4)=75 students

Students born in 1999= 75*2=150 students

Students born in 2001=150*(1/3) =50 students

Students born in 1998=50*(1/2) =25 students

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Sholpan [36]

Answer:

Step-by-step explanation:

-2m - 5n = 7m - 3n

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4 years ago
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Question
mixer [17]

The intervals are given as follows:

  • In range notation: [-282, 20,320].
  • In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}

<h3>What is the range of elements notation for interval?</h3>

The range of elements notation for interval is given by:

[a,b].

In which:

  • a is the smallest value.
  • b is the greatest value.

In this problem these values are given by:

a = -282, b = 20,320.

Hence the interval in range notation is given by:

[-282, 20,320].

<h3>How to write the interval in set-builder notation?</h3>

The same interval can be written as follows, using set-builder notation?

{x|x ∈ ℝ, a <= x <= b}

Hence, for the situation described in this problem, the set-builder notation for the values is:

{x|x ∈ ℝ, -282 <= x <= 20,320}

More can be learned about notation of intervals at brainly.com/question/27896097

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2 years ago
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Setler79 [48]

Answer:

1/2

Step-by-step explanation:

We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.

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sdas [7]
Divide both the numerator and denominator by the gcf, which is 3.

3/3=1
6/3=2

Final answer: 1/2
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3 years ago
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