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3 years ago

PLEASE HELP WILL MARK BRAINLIEST (not if you get it wrong) Just with the median question :)

Mathematics

1 answer:

STALIN [3.7K]3 years ago

6 0

Answer:

Group one has the larger median

Step-by-step explanation:

Group One:

By taking off 8 on both ends we see that the median is 53 for group one.

33, 35, 40, 41, 43, 46, 48, 49, 53, 54, 55, 58, 58, 58, 62, 62, 67

Group two:

By taking off 8 on each end as well we get 47 and 49.

35, 38, 40, 41, 42, 43, 47, 47, 47, 49, 50, 50, 53, 54, 57, 61, 66, 69

we then take the average of the two numbers

47 + 49 = 96

96 / 2 = 48

You might be interested in

What’s the answer to 7^3x=54

HACTEHA [7]

Answer:

x = 54/343

Step-by-step explanation:

$7^3x=54\\\rightarrow 7^3 = 343\rightarrow \text {Solve Exponents} \\343x=54\\\frac{343x}{343} =\frac{54}{343}\\x =\frac{54}{343}$

5 0

4 years ago

If X=20°, Y=135°, what will Z be

Veronika [31]

The value of Z would be 225°

<h3>What is the angle at a point?</h3>

The angle at a point are angles that add up to 360°

Thus, X + Y + Z = 360°

X = 20°

Y = 135°

Then, Z = 360° - X - Y

Z = 360° - 20° + 135°

Z = 360° - 155°

Z = 205°

Therefore, the value of Z is 205°

Learn more about angle at a point here:

brainly.com/question/24839702

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6 0

2 years ago

HELP PLEASE

Arturiano [62]

The plane will end up flying 5.02°.

The plan's speed relative to the ground will be 645.91 km/hr.

Solution:

Use the cosine formula,

$a^{2}=b^{2}+c^{2}-2 b c \cos A$

Substitute the given values in the formula,

$\mathrm{R}^{2}=700^{2}+80^{2}-(2 \times 700 \times 80 \times \cos 45^\circ)$

$\mathrm{R}^{2}=490000+6400-(112000 \times\frac{1}{\sqrt{2} } )$

$\mathrm{R}^{2}=496400-79195.95$

$\mathrm{R}^{2}=417204.049$

Taking square root on both sides, we get

R = 645.91 km/hr

This is the grouped speed of the aircraft.

To find θ use sine rule.

$$\frac{\sin C}{c}=\frac{\sin A}{a}$

$$\frac{\sin \theta}{80}=\frac{\sin 45}{645.91}$

Do cross multiplication, we get

$${\sin \theta}}=\frac{\sin 45}{645.91}\times 80$

$${\sin \theta}}=\frac{\frac{1}{\sqrt{2} } }{645.91}\times 80$

sin θ = 0.0875

θ = 5.02°

This is known as the drift angle and is the correction the pilot should apply to remain on course.

The heading is the direction the aircraft's nose is pointing which is

The track is the actual direction over the ground which is θ = 5.02°

An alternative method to this would be to separate each vector into vertical and horizontal components and add.

The resultant can be found using Pythagoras.

7 0

4 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

8 0

4 years ago

Paper clips costs $7.20 what is the unit price of the paper clips

Olegator [25]

I could help you, but how many paper clips were there? divide 7.20 by whatever number it is...

6 0

4 years ago