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3 years ago

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Suppose you go to a company that pays 0.05 for the first day, 0.1 for the second day, 0.2 for the third day and so on. If the da

ily wage keeps doubling, what will your total income be for working 30 days ?
Total Income =

1 answer:

tekilochka [14]3 years ago

5 0

Answer:

I think the correct answer is $26,843,545.6

Step-by-step explanation:

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Please help asap I HV a time

nikdorinn [45]

Answer: 382

Just add 300+70+12 and you get 382

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2 years ago

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 162 pounds and a standard de

never [62]

Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004

<u>Using the relation</u> ::

Zscore =(X - μ) ÷ σ

The mean, μ = np = (162 × 19) = 3078

The standard deviation, σ = 28 × √19 = 122.049

<u>The Zscore</u> :

Zscore = (3401 - 3078) ÷ (122.049)

Zscore = 2.65

Hence,

P(Z > 2.65) = 1 - P(Z < 2.65)

Using a normal distribution table :

P(Z > 2.65) = 1 - 0.9959

P(Z > 2.65) = 0.004

Learn more : brainly.com/question/25204474

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2 years ago

Part B The mass of an average grain of rock salt is about 40 times the mass of an average grain of table salt. If you multiply t

Lady bird [3.3K]

Answer: Its (A)

Step-by-step explanation:

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2 years ago

Select from the value that correctly completes the sentence. The value of x is

posledela

Step-by-step explanation:

I hope it helps you......

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2 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago