Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
Answer:
Step-by-step explanation:
The given quadratic expression is
3x² - 9x + 6
Dividing each term in the expression by 3 in order to simplify it further, it becomes
x² - 3x + 2 = 0
We would determine two numbers such that their sum or difference is -3x and their product is 2x².
The two numbers are - 2x and - x.
Therefore,
x² - 2x - x + 2
x(x - 2) - 1(x - 2)
(x - 1)(x - 2)
When the expression is factored completely, it is equivalent to
(x - 1)(x - 2)
Based on the lengths of the given triangles and the length of segment BD, the length of segment AD is 22.20.
<h3>What is the length of segment AD?</h3>
The triangle ABC is a right angled triangle with segment AB being the hypothenuse.
We can therefore find this length using the Pythagoras Rule:
Hypothenuse ² = a² + b²
Hypothenuse ² = 28.6² + 23.2²
Hypothenuse ² = 1,356.20
Hypothenuse = √1,356.20
= 36.83
Length of AD:
= AB - BD
= 36.83 - 14.60
= 22.2
Find out more on the Pythagorean theorem at brainly.com/question/343682.
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Answer:
it look like its 4 and the 4 over 4/5 I think
