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drek231 [11]
3 years ago
7

The travelers are adding a new room to their house. the room will be a cube with volume 3375 ft.³.they are going to put in hardw

ood floors, the contractor charges $10 per square foot. how much will the hardwood floors cost?

Mathematics
2 answers:
Talja [164]3 years ago
7 0

Answer:

$ 2250

Step-by-step explanation:

3375 = s³

s = ∛3375

s = 15 ft.

floor area = s² = (15 * 15)

floor area = 225 ft²

the contractor charges $10 per ft².

therefore,  

the hardwood cost = 225  x  $10 = $2250

FinnZ [79.3K]3 years ago
4 0

Answer:

$2,250.

Step-by-step explanation:

So first, we need to find the area of the floor (the side shaded green). To do so, we first need to find the length of the one side of the room.

Since we know that the room is a cube, all side lengths are equivalent. And since we are given that the volume of the room is 3375, we can find the length of the side.

The volume of a cube is given by the formula:

V=s^3

Substitute 3375 for V:

s^3=3375

Take the cube root of both sides:

s=\sqrt[3]{3375}=15

So, the side length of the room is 15.

This means that the area of the floor is:

A=(15)^2\\A=225\text{ in}^2

They charge $10 per square foot. There are 225 square feet. Thus, the total cost will be:

10(225)=$2250

$2,250.

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