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notka56 [123]
3 years ago
5

In a country that only wants girls, every family continues to have children until they have a girl. If they have a boy, they hav

e another child. If they have a girl, they stop. What is the proportion of boys to girls in the country
Mathematics
1 answer:
Alik [6]3 years ago
7 0

Complete Question

In a country in which people only want Girls, every family continues to have children until they have a Girl. If they have Girl, they stop. If they have boy, they will continuous have child. Assuming that the birthrate of Girl is 52%, what is the proportion of Girl in the country?

Answer:

0.52

Step-by-step explanation:

From the question we are told that

52% is the birthrate of Girls

Therefore

       \frac{52}{100} =0.52

0.52 is the proportion of Girls to boys in that country

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3 years ago
H(x)=-3x-4 What is g(6)
mrs_skeptik [129]

Answer:

h(6)=-22

Step-by-step explanation:

h(x)=-3x-4

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6 0
3 years ago
Cone A is divided into Cone B and Frustum C. B A 12cm C 20cm 20cm Express the volume of Frustum C as a fraction of the volume of
zaharov [31]

The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³

<h3>Calculation of a frustum</h3>

The volume of cone A V=πr²h/3

Where radius = 20cm

The volume of cone B = V=πr²h/3

Where radius = 12cm

Therefore volume of frustum =

V=π * 20² * h/3 - π * 12² *h/3

The variables will cancel out each other

V = 20² - 12²

V = 400- 144

V = 256cm³

Therefore, the volume of the frustum(C) = 256cm³

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7 0
2 years ago
How do i solve this?
Leni [432]

Answer: this is hard I hate math sorry

Step-by-step explanation:

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3 0
3 years ago
Vertex form is f(x)=a(x-p)^2 +q. How do i determine a?
slamgirl [31]
Y1 is the simplest parabola.  Its vertex is at (0,0) and it passes thru (2,4).  This is enough info to conclude that y1 = x^2.

y4, the lower red graph, is a bit more of a challenge.  We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).

Let's try this:  assume that the general equation for a parabola is 
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-3-(-4) = a(2-0)^2.  Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.

The equation of parabola y4 is   y+4 = (1/4)x^2

Or you could elim. the fraction and write the eqn as 4y+16=x^2, or

4y = x^2-16, or    y = (1/4)x - 4.  Take your pick!  Hope this helps you find "a" for the other parabolas.


8 0
3 years ago
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