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posledela
3 years ago
11

Two cars start from the same place at the same time but travel in opposite directions. One car averages 42 miles per hour and th

e other averages 51 miles per hour. In how many hours will they be 651 miles apart
Mathematics
1 answer:
Andrew [12]3 years ago
7 0
The two cars will be 651 miles apart, when the sum of the distances covered by the two cars is 651 miles.

distance = speed x time.
Let the time covered when they are 651 miles apart be x, then:
42x + 51x = 651
93x = 651
x = 651/93 = 7.

Therefore, the two cars will be 651 miles apart in 7 hours.
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babymother [125]
The answer is b for your answer
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3 years ago
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Nina walks on the path around the pond at the city park.
PtichkaEL [24]

Answer: 0.5

Step-by-step explanation:

8 0
3 years ago
The answer please. (F-g)(-3)
ad-work [718]
There are two ways to do this
Method 1:

Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1

Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38

-----------------------------------------

Method 2:

Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48

Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10

Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38

-----------------------------------------

Whichever method you pick, the answer is: 38

4 0
3 years ago
AB = x + 15 DC = 4x AD = x + 10 BC = ? Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent. Show
dexar [7]

Answer:

BC=15\ units

Step-by-step explanation:

we know that

In a parallelogram opposite sides are congruent

In this problem

we have that

AB and DC are opposite sides

AD and BC are opposite sides

so

AB=DC

AD=BC

step 1

Find the value of x

AB=DC

substitute the given values

x+15=4x

solve for x

4x-x=15

3x=15

x=5\ units

step 2

Find the length of AD

we have that

AD=x+10

substitute the value of x

AD=5+10=15\ units

step 3

Find the length of BC

Remember that

AD=BC ----> by opposite sides

therefore

BC=15\ units

6 0
3 years ago
PLEASE HELP ME!!!
Ede4ka [16]

The roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}.

Here the given quadratic equation is 5x^2-13x+7=0. Here a=5,b=-13,c=7.

The roots are

x=\frac{13 \pm \sqrt{13^2-4*5*7}}{2*5} \\ x=\frac{13 \pm \sqrt{29}}{10}

7 0
3 years ago
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