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kodGreya [7K]
3 years ago
13

Plz help me i will give you brainliest

Mathematics
2 answers:
artcher [175]3 years ago
8 0
The person above is correct
ra1l [238]3 years ago
6 0

Answer:

#2 10 bags

#3 0.882

#4 0.952

Step-by-step explanation:

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What is the fraction form of 0.73
padilas [110]
The fraction form of 0.73 is 73/100
6 0
3 years ago
Read 2 more answers
Veena's father is 7 years older than five times the age of Veena. If his age is 37. find Veena's age.​
ra1l [238]

Step-by-step explanation:

let Veena father be x and Veena be y

x=5y+7

x=37

37=5y+7

30=5y

y=6

Veena is 6 year old

7 0
4 years ago
In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
Diano4ka-milaya [45]

Answer:

65.03square units.

Step-by-step explanation:

Find the diagram in the attachment below.

Area of the sector HJK = theta/360° × πr²

theta is the angle subtended by the sector = ∠HJK = 92°

r is the radius = HJ = 9units.

Substituting the given values in the formula:

Area of sector HJK = 92°/360° × π(9)²

Area of sector HJK = 23,399.28/360

Area of sector HJK = 65.03 square units to nearest hundredth

6 0
3 years ago
Max drove his car 389 miles on 18.6 gallons of gas how many miles per gallon did Max’s vehicle get to the nearest 10th of a mile
Vlada [557]

Answer:

209.14 miles

Step-by-step explanation:

6 0
3 years ago
The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
3 years ago
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