The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
What is Quadratic equation?
An algebraic equation of the second degree is called a quadratic equation.
Given that;
A quadratic equation is;
3x² = -12x - 15
Now, The equation is written as;
3x² + 12x + 15 = 0
Take 3 common, we get;
3 (x² + 4x + 5) = 0
x² + 4x + 5 = 0
Factorize the equation by using Sridharacharya Formula;
x = - 4 ± √4² - 4*1*5 / 2*1
x = -4 ± √16 - 20 / 2
x = - 4 ± √-4 / 2
Since, √-1 = i
x = -4 ± 2i / 2
x = - 2 ± i
It gives two values of x as;
x = - 2 + i
And, x = - 2 - i
Hence, The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
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Answer:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Step-by-step explanation:
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
0.6 + 15b + 4 = 25.6 all equivelant
Answer:
6th term
Step-by-step explanation:
95=55+8n-8
95-55=8n-8
40+8=8n
48/8=8n/8
6=n
Step-by-step explanation:
80+60+x+51= 180
191+x= 180
x= -11
12 pounds divided up between 27 sandwiches is 0.44 pounds for each sandwich. 12/27=0.44
