Answer:
$15.625
Step-by-step explanation:
Let the revenue collected be R and price per spectator be p then the number of spectators be N. Therefore
R=Np
Using equation of slope of y=mx +c where m is gradient and c is y-intercept
When p=$11, N=27000 and when p=$8, N=31000
The gradient, m will be

To get the y-intercept
N=-1333.33p+c
When spectator number n is 27000, the price p is $11
27000=-1333.33(11)+c hence we solve c
c=27000+(11*1333.33)= 41666.67
Therefore, the linear equation is
N=-1333.33p+ 41666.67
Substituting the linear equation into R=Np we obtain
R=p(-1333.33p+41666.67)
 
 
To obtain maximum revenue, we differentiate the above with respect to price hence obtain
0=2*-1333.33p+41666.67

Therefore, the price that maximizes revenue is $15.625
 
        
             
        
        
        
Answer:
Step-by-step explanation:
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Answer: a. 154 is larger than 27 by 127.
b. 25 is larger than 12 by 13.
c.135 is larger than 127 by 8.
d.46 is larger than 24 by 22.
Step-by-step explanation:
Subtract second number from the first number.
a. 154 and 27
Difference=
Hence, 154 is larger than 27 by 127.
b. 25 and 12
Difference=
Hence, 25 is larger than 12 by 13.
c. 135 and 127
Difference=
Hence, 135 is larger than 127 by 8.
d. 46 and 24
Difference=
Hence, 46 is larger than 24 by 22.
 
        
                    
             
        
        
        
Given: It is given that the length of the painting is 24 inches and the width is  11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:



The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in


Now to calculate the area of mat subtracts the area of painting from the area of the mat.



Hence, the area of the mat is 246 in².