Answer:
its a 50 degree angle i think.
Step-by-step explanation:
its a smaller size in scale of the bigger one.
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
1 is 1
2 is going to be -8x to the second minus 6 x
3 is 3 plus three x two minus seven x plus two xx 2 minus 6xto the 2
4 is 11
Answer:
adult $8.00
child $5.50
Step-by-step explanation:
Let the price of 1 adult ticket = x.
Let the price of 1 child ticket = y.
2x + 4y = 38
3x + 3y = 40.5
Multiply the first equation by 3. Multiply the second equation by -2. Then add them.
6x + 12y = 114
(+) -6x - 6y = -81
-----------------------------
6y = 33
y = 33/6
y = 5.5
2x + 4y = 38
2x + 4(5.5) = 38
2x + 22 = 38
2x = 16
x = 8
Answer:
adult $8.00
child $5.50
