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Alexandra [31]
2 years ago
5

Evaluate 4 + (m - n) When m = 7 and n = 5.

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
7 0

Answer:

7 - 5 = 2

2 + 4 = 6

Evaluate parenthesis first.

Add 4 to the number you got from subtracting 7 and 5.

ziro4ka [17]2 years ago
4 0
1. substitute:
4+(7-5)
2. simplify:
4+2
3. evaluate:
6
the answer is 6.

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1.) 2x−9y=14<br><br><br> 2.) x=−6y+7<br> ​ <br> please help!!
harkovskaia [24]

Answer

7,0

Step-by-step explanation:

Substitute -6y+7 into problem one where the x is

distribute the 2 and subtract the 9 y and you will get

-21y+14=14

subtract 14 from both sides and it will be -21y=0 so y will be 0

substitute the 0 into equation 2 and find x=7

7 0
3 years ago
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$44.398 round to the nearest cent
sladkih [1.3K]

Answer:

44.40

Step-by-step explanation:

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2 years ago
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Find an equivalent expression for each expression by simplifying. (3x - 5y) + 7y
sertanlavr [38]
This question is quite simple really. They are basically asking you to combine like terms. You have two different figures with the variable y, so you just combine the them. It would then be 3x + 2y. You cannot simplify this equation any further since there is nothing to solve for or anymore like terms to combine.
4 0
2 years ago
Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1,y1),(
svetoff [14.1K]
I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:

(0-1)^2=4p(16-20)

Solving for p, p=-1/16.

Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:

(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1

Here, we have two values of x

x=sqrt(5)+1 and
x=-sqrt(5)+1

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5 0
3 years ago
The frequency of vibrations of a vibrating violin string isgiven by
arlik [135]

Answer:a. [tex] $f\propto  L$ [\tex]

b. [tex] f \propto \sqrt{T} [\tex]

c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]

I. Decrease in length increases leads to increase in pitch.

II. Increase in tension leads to increase in pitch.

III. Increase in linear density reduces the pitch

Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.

II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.

III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.

7 0
3 years ago
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