Solve for m and b (5,14) and (3,10)

Mathematics

1 answer:

Elis [28]3 years ago

6 0

Y=mx+b

Y1-Y2/X1-X2

14-10/5-3 = 4/2 = 2

Plug in (3,10):
(10)=2(3)+b

Solve:
10=6+b

B=4
M=2

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Two pedestrians simultaneously left two villages 27 km apart and walked toward each other. the first one walked 4 km per hour, a

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Step 1: Assign variable for the unknown that you need to find.

Let ' t ' be the number of hours it took for the pedestrians to meet.

Step 2: List the give details

Speed of first pedestrian = 4 km/hr.

Speed of second pedestrian = 6 km/hr.

Distance between two pedestrians = 27 km.

Step 3: Set up an equation

The relationship between speed, distance and time is given below:

$Distance= \; Rate \times Time$

The first one walked 4 km per hour, distance traveled by first pedestrian is given below:

$Distance_{1^{st} \; pedestrian} \; = \; 4t\\\\Distance_{2^{nd} \; pedestrian} \; = \; 6t$

Two pedestrians simultaneously left two villages 27 km apart and walked toward each other.

$Distance_{1^{st} \; pedestrian} +Distance_{2^{nd} \; pedestrian} =27\\\\4t+6t=27\\Combine \; Like \; Terms\\\\10t=27\\Dividing \; 10 \; on \; both \; sides\\\\ \frac{10t}{10} = \frac{27}{10} \\Simplifying \; fraction \; on \; both \; sides\\\\t=2.7 \; hours$