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2 years ago

A system of two linear equations with two variables is shown below.

Mathematics

1 answer:

Orlov [11]2 years ago

6 0

{ 3-y=2x
{ x+1/2y=3/2

{ -y=2x-3
{ 1/2y=3/2-x

{ y=-2x+3
{ y=3-2x

-2x+3=3-2x

(x,y) = (x,-2x+3)

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Answer:

Multiply the divisor by a power of 10 to make it a whole number.

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Divide the dividend by the whole-number divisor to find the quotient.

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2 years ago

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patriot [66]

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Step-by-step explanation:

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What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

zheka24 [161]

Answer:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$ $=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

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