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stepan [7]
3 years ago
8

What is b called in a triangle? PLEASE HURRY!

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

B Is called legs

Step-by-step explanation:

OverLord2011 [107]3 years ago
8 0

Answer:

what are the answers ?

Step-by-step explanation:

I cant see the other answers I only see leg

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I need help look at the picture attached
Vinil7 [7]

Answer:

340.8 m

Step-by-step explanation:

Find the area of rectangles:

15 x 8 = 120

6x8=48

16x8=128

Find area of triangle:

1/2 5.6 x 16 = 44.8

Add together:

120 + 48 + 128 + 44.8 = 340.8 m

Hope this helps :)

7 0
3 years ago
Solve the equation x^6+3x^5+x^4-5x^3-6x^2-2x=0 in the real number system
koban [17]
First, pull out a factor of x.

x^6+3x^5+x^4-5x^3-6x^2-2x=x(x^5+3x^4+x^3-5x^2-6x-2)

Notice that when x=-1 (which you can arrive at via the rational root theorem), you have

(-1)^5+3(-1)^4+(-1)^3-5(-1)^2-6(-1)-2=-1+3-1-5+6-2=0

which means you can pull out a factor of x+1. Upon dividing you get

\dfrac{x^5+3x^4+x^3-5x^2-6x-2}{x+1}=x^4+2x^3-x^2-4x-2

The rational root theorem will come in handy again, suggesting that x=-1 appears a second time as a root, which means

\dfrac{x^4+2x^3-x^2-4x-2}{x+1}=x^3+x^2-2x-2

Now this is more readily factored without having to resort to the rational root theorem. You have

x^3+x^2-2x-2=x^2(x+1)-2(x+1)=(x^2-2)(x+1)

so in fact, x=-1 shows up as a root for a third time.

So, you have

x^6+3x^5+x^4-5x^3-6x^2-2x=x(x+1)^3(x^2-2)=0

Two roots are obvious, x=0 and x=-1 (with multiplicity 3). The remaining two are given by

x^2-2=0\implies x^2=2\implies x=\pm\sqrt2
3 0
4 years ago
What is 10 times 2.50?
dolphi86 [110]
Twenty five dollars answeris

4 0
3 years ago
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(Need help) (ASAP) <br><br> Point: 18
Anastasy [175]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
The world record for the 100 m sprint is 9.77 s. How long would it take to run 1 m at this speed?
svlad2 [7]

Answer:0.85

Step-by-step explanation:

4 0
3 years ago
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