Answer:
The sequence is arithmetic with a common difference of -10
Step-by-step explanation:
From the question, we want to determine if the sequence is arithmetic or geometric
From the question
f(1) = 5
f(2) = -5
f(3) = -15
Mathematically for the common difference;
f(3) - f(2) = f(2) - f(1)
Since;
-15-(-5) = -5-5
-10 = -10
Since the common difference here is same , then the sequence is arithmetic with a common difference of -10
Answer:
<h2>x = 30°</h2>
Step-by-step explanation:
Since the figure above is a triangle, all it's angles sum up to 180°
To find x , add up all the angles and subtract them from 180°
That's
57 + 93 + x = 180
150 + x = 180
x = 180 - 50
We have the final answer as
<h3>x = 30°</h3>
Hope this helps you
A)
![\bf 1990-1910=80\leftarrow t \\\\\\ P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}} \\\\\\ P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}](https://tex.z-dn.net/?f=%5Cbf%201990-1910%3D80%5Cleftarrow%20t%0A%5C%5C%5C%5C%5C%5C%0AP%28t%29%3D8000%282%29%5E%7B-%5Cfrac%7Bt%7D%7B29%7D%7D%5Cimplies%20P%2880%29%3D8000%282%29%5E%7B-%5Cfrac%7B80%7D%7B29%7D%7D%0A%5C%5C%5C%5C%5C%5C%0AP%2880%29%3D8000%5Ccdot%20%5Ccfrac%7B1%7D%7B2%5E%7B%5Cfrac%7B80%7D%7B29%7D%7D%7D%5Cimplies%20P%2880%29%3D%5Ccfrac%7B8000%7D%7B%5Csqrt%5B29%5D%7B2%5E%7B80%7D%7D%7D)
and surely you know how much that is.
b)
since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
Answer:
new slope = 4/3
Step-by-step explanation:
-3/8 is perpendicular to the new slope
=> new slope = -8/3 * -1/2
= 8/6
= 4/3
please give me brainliest if it is helpful for you
Answer:
Ver explicacion
Step-by-step explanation:
La frecuencia de una onda se define como el número de ciclos completos que realiza una partícula en un segundo.
f = n / t = 15 ciclos / 3 segundos = 5 ciclos por segundo o Hertz
El período de una onda es el tiempo que tarda la onda en realizar una oscilación o ciclo completo.
T = t / n = 3/15 = 0,2 segundos
