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2 years ago

6

A triangular prism is 12.7 yards long. It has a triangular face with a base of 19 yards. The volume of the prism is 1,894.205 cu

bic yards. What is the height of its triangular face?

1 answer:

shusha [124]2 years ago

8 0

Answer: I don’t know

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Round $38.09 to the nearest dollar<br> $38<br> $40<br> $30<br> $39

Veronika [31]

Answer:

$38

Step-by-step explanation:

Since the last two numbers aren't over 50, we would round down. This leaves you with $38.

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3 years ago

If copies cost .08 per copy but you buy a fuscount card for 7.50 and the copies are .05 how many copies will make it worth the d

timurjin [86]

Answer:

<u>The number of copies that will make it worth the discount card is 250.</u>

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Cost per copy without discount = US$ 0.08

Cost per copy with discount = US$ 0.05

Cost of discount card = US$ 7.50

2. How many copies will make it worth the discount card?

For finding out this number of copies, we will use the following equation:

x = Number of copies that will make it worth the discount card

0.08x = 0.05x + 7.50

0.03x = 7.50 (Like terms)

3x = 750 (Multiplying by 100 at both sides)

x = 250 (Dividing by 3 at both sides)

<u>The number of copies that will make it worth the discount card is 250.</u>

Note: Same answer to question 14127203, answered by me today.

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3 years ago

What two numbers is 94 between

levacccp [35]

94 is between 93 and 95

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3 years ago

Read 2 more answers

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

so

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

so

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

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2 years ago

a square pyramid has a base with a side length of 4 feet and lateral faces with heights of 3 feet. whay is the lateral area of t

Nastasia [14]

The answer would be 6 because you need to multiply the L by the H divided by to: 4x3+12 12/2 +6

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3 years ago