We calculate the speed by dividing the distance over time:
s = d/t
So the distance described in the problem is always the same, A to B and B to A.
But we are told that;
7 = d/t
7 = 2d/(t + 2)
that is, the first equation say that at speed 7 km/h a distance d is walked in a time t
the second equation say that at a average speed of 7 (that is 8 on one way and 6 in the other: 8 + 6 = 14, half of it), twice the distance is walked in a time equal to the first time plus 2 minutes.
So we have a system of linear equations, 2 of them with two unknowns, we can solve that:
7 = d/t
7 = 2d/(t + 2<span>)
</span>lets simplify them:
7t = d
7(t + 2) = 2d
7t = 2d - 14
we substitute the first in the second:
<span>7t = 2d - 14
</span><span>7t = d
</span>so:
d = 2d - 14
d = 14
so the distance between A and B is 14 km
Answer:
Answer
0.109589 millimeters per day.
Explanation
10 mm = 1 cm
4 cm = 4 × 10
= 40 mm
365 days = 1 year
rate to millimeters per day = 40 mm in 365 days
= 40/365 mm/day
= 8/73 mm/day
or = 0.109589 mm/day.
Rate to millimeters per day = 0.109589 millimeters per day.
Step-by-step explanation:
We know that g(x) = \frac{3}{x^2+2x}
We have to find g^-1(x) or inverse of g(x)
Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y
g(x) = y = \frac{3}{x^2+2x}
⇒ y × (x² + 2x) = 3
⇒ yx² + 2xy = 3
⇒ yx² + 2yx - 3 = 0
Determining the roots of x using:
x = 
OR x = 
, where a is coefficient of x², b is coefficient of x, and c is the constant
⇒ x = 
OR x = 
⇒ x = 
OR x = 
Hence, g^-1(x) = OR x =
Well you can start by drawing a triangle with the information
the size of angle B can be found using the Law of Sine
the size of angle C can be found using angle sum of a triangle.
The length of side c can be found using the Law of Cosines
hope it helps
Answer:
B. 3×7×7
Step-by-step explanation:
147
49 * 3
7 * 7 * 3
