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3 years ago

Find the volume of a rectangular prism with length 20 m,

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

4 0

Answer:

V= 270m³

Step-by-step explanation:

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A rectangular garden is to be constructed using a rock wall as one side of the garden and wire fencing for the other three sides

LiRa [457]

Answer:

600

Step-by-step explanation:

6 0

3 years ago

A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

3 years ago

1/2(3/4n+ 9) and 2(12 + 8x) -3(4x -9) i need help with these two

Ghella [55]

I dont know if this is right but the answer to 2(12+8x)-3(4x-9) might be 4x+51?

5 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEEEEEEE

Licemer1 [7]

Answer:

The area is 35

The perimeter is 24

Step-by-step explanation:

You can count the individual units of the length and the width of the rectangle.

The width is 5, the length is 7

The area is 5*7=35

The perimeter is 5+5+7+7=24

6 0

3 years ago

Read 2 more answers

What is PA <br> Enter your answer in the box

SSSSS [86.1K]

Answer:

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒ $PE^{2}=PK^{2}-KE^{2}$

⇒ $PE=\sqrt{PK^{2}-KE^{2} }$

⇒ $PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒ $PE=3$

Therefore, $PA=3$

3 0

3 years ago