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solmaris [256]
3 years ago
11

Find the volume of a rectangular prism with length 20 m,

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

V= 270m³

Step-by-step explanation:

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A rectangular garden is to be constructed using a rock wall as one side of the garden and wire fencing for the other three sides
LiRa [457]

Answer:

600

Step-by-step explanation:

6 0
3 years ago
A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op
Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, \dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h

Volume of cone is given by

V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3

By differentiating with respect to time t, we get that

\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}

Now,  the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie \dfrac{dv}{dt}=-4\ in^3

and h = 2 inches deep.

-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0
3 years ago
1/2(3/4n+ 9) and 2(12 + 8x) -3(4x -9) i need help with these two
Ghella [55]
I dont know if this is right but the answer to 2(12+8x)-3(4x-9) might be 4x+51?
5 0
3 years ago
Read 2 more answers
HELP ME PLEASEEEEEEEEEE
Licemer1 [7]

Answer:

The area is 35

The perimeter is 24

Step-by-step explanation:

You can count the individual units of the length and the width of the rectangle.

The width is 5, the length is 7

The area is 5*7=35

The perimeter is 5+5+7+7=24

6 0
3 years ago
Read 2 more answers
What is PA <br> Enter your answer in the box
SSSSS [86.1K]

Answer:

3

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : PK^{2}=PE^{2}+KE^{2}

⇒PE^{2}=PK^{2}-KE^{2}

⇒PE=\sqrt{PK^{2}-KE^{2} }

⇒PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }

⇒PE=3

Therefore, PA=3

3 0
3 years ago
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