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balandron [24]
3 years ago
13

What do these (>, ≥, <, ≤) mean

Mathematics
1 answer:
AysviL [449]3 years ago
7 0

Answer: <less than >greater than ≥ greater than or equal to ≤ less than or equal to

Step-by-step explanation:

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Find the value of x. Round to the<br> nearest tenth.<br> 26<br> 12<br> х<br> X=<br> = [?]
levacccp [35]

Answer:

X = 5.9 (in degree mode)

Step-by-step explanation:

Do the following:

12(tan26) = X

Plugging this into a calculator, you will get:

X = 5.9 (in degree mode)

7 0
3 years ago
Directions:
cricket20 [7]
1. obtuse angle is shown, 45° is missing.
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6. acute angle is shown, 100° is missing.
7 an obtuse angle and a acute angle are shown, 54° (for number 1) and 126° (for number 2) are missing.
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5 0
3 years ago
URGENT!!!<br> Which function is shown in the graph?
katrin2010 [14]

Answer:

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5 0
2 years ago
A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
3 years ago
Show work / explain it ​
notsponge [240]

Answer:

-4

Step-by-step explanation:

look at the screenshot

6 0
3 years ago
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