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The true average strain in a way that conveys information about precision and reliability is 27.314.
Given that sample size is 20, mean is 26%, standard deviation is 3.4, confidence level is 95%.
We have to calculate the true average strain in a way that conveys information about precision and reliability.
We have to use t test in our problem because sample size is less than 30.
Weknow that,
t=x bar-μ/s
where μ is sample mean,
s is sample standard deviation.
Degree of freedom=n-1
=20-1
=19
T value at 95% confidence interval=1.7281
put the values in the formula of t given above.
1.7291=x bar-26/3.4/
1.7291=xbar-26/3.4/4.47
1.7291= x bar-26/0.76
1.7291*0.76=x bar-26
1.314=x bar-26
x bar=26+1.314
x bar=27.314
After rounding it will be 27.31
Hence the true average strain in a way that conveys information about precision and reliability is 27.31%.
Learn more about t test at brainly.com/question/6589776
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