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In-s [12.5K]
3 years ago
15

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its

speed, as time increases?

Mathematics
2 answers:
Savatey [412]3 years ago
8 0
The graph would almost look like this

Vilka [71]3 years ago
8 0

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?




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What property is 1(5x+6)
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Distributive i think. Because you’d have to distribute the 1 to (5x+6)
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Alejandro has 128 ounces of dog food.He feeds his dog 8 ounces each day.How many days will the dog food last
AnnyKZ [126]
16 days

Divide 128oz(starting point) by 8(how many you feed everyday)


An equation would look something like this:

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3 0
4 years ago
Read 2 more answers
Mike has a large amount of chocolate spheres, each chocolate sphere having a radius of 2 inches.
USPshnik [31]

The value of the expression Z² + Q² is 4321

<h3>How to evaluate the expression?</h3>

The radius of the chocolate spheres is given as:

r = 2

The maximum number of chocolates that can fit in a spherical capsule is calculated as:

Max = R³/r³

Where:

R represents the radius of the sphere.

For the spherical capsule whose radius is 8 inches, we have:

Z = 8³/2³

Evaluate

Z = 64

For the spherical capsule whose radius is 5 inches, we have:

Q = 5³/2³

Evaluate

Q = 15.625

Remove decimal

Q = 15

So, we have:

Z² + Q² = 64² + 15²

Evaluate the exponent

Z² + Q² = 4096 + 225

Evaluate the sum

Z² + Q² = 4321

Hence, the value of Z² + Q² is 4321

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brainly.com/question/1972490

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3 0
2 years ago
The value stored in variable s at the end of the execution of the loop could best be described as __________. Assume that all va
Angelina_Jolie [31]

Answer:

It will describe the sum of the numbers scanned.

As we can see whatever you scan or take input it will be added to s without any condition. So at the end, sum of all scanned number will be save in variable s

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What is 5.6 less than 25.3
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Answer:

19.7

Step-by-step explanation:

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