Using the law of cosine:
Cosine(angle) = Adjacent leg / Hypotenuse
You are given the angle, and the adjacent leg and need to solve for X, which is the hypotenuse.
Using the formula above you have:
Cosine(58) = 17 / x
Solve for x by dividing 17 by cos(58)
x = 17 / cos(58)
x = 32.08
u19=-71.74
Step-by-step explanation:
u5=a+4d=-3.7....(1)
u15=a+14d=-52.3....(2)
-10d=48.6
d=-48.6/-10
d=-4.86
Substitute-4.86 into....(1)
u5=a+4(-4.86)=-3.7
a+(-19.44)=-4.7
a=-3.7-(-19.44)
a=15.74
19term=a+18d=?
=15.74+18(-4.86)
=15.74+(-87.48)
19th term =-71.74
Answer:
25
Step-by-step explanation:
Divide 500/20
I think C... I'm guessing cause my math is wrong
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
