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2 years ago

Combine like terms: -4x+3-7x-8

Mathematics

1 answer:

Sedaia [141]2 years ago

4 0

Answer:

Basicly you just combine the terms that are the same. Combine -4x and -7x. Also combine 3 with -8.

Step-by-step explanation:

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HELP PLEASE IM STUCK

andre [41]

Answer:

360-(124+124)= 360-248=122 divided by 4=30.5

6 0

3 years ago

Solve for v.<br> Simplify your answer as much as possible.<br><br> 5+2v=3

Ksenya-84 [330]

Answer:

v= -1

Step-by-step explanation:

5+2v=3

2v=3-5

2v= -2

v= -2/2

v= -1

5 0

3 years ago

Read 2 more answers

Why do bank charges transaction fees

r-ruslan [8.4K]

Answer:To make a profit and pay operating expenses, banks typically charge for the services they provide. When a bank lends you money, it charges interest on the loan. Even fee-free checking and savings accounts have some fees. ...

Step-by-step explanation:

7 0

3 years ago

Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of

GuDViN [60]

So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

$\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}
\\\\\\
\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}$

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20

now the "p" part... ends up as $\bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}$

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M

7 0

3 years ago

Answer these 2 questions please

Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

$\frac{7}{8}-\frac{1}{4}$

Now, to subtract these, we want to make it so the denominators are the same, or the numbers on the lower half are the same. (One way to explain why this is true is: $\frac{a}{b}-\frac{c}{b}=a\frac{1}{b}-c\frac{1}{b}=(a-c)\frac{1}{b}=\frac{a-c}{b}$ ). Now, to make it so the denominators are the same, we can multiply the second fraction, 1/4, by 2/2 as 2/2 is essentially 1, and multiplying by 1 will get the same result, just with a denominator switched in this case. Doing this, we get:

$\frac{7}{8}-\frac{1}{4}\cdot\frac{2}{2}$

$\frac{7}{8}-\frac{2}{8}$

Now, subtracting the numerators, we get:

$\frac{5}{8}$ yards of string will remain.

Question 2:

For this, we are combining these two thicknesses, and thus we add 1/4 to 7/12. This gives us the equation:

$\frac{1}{4}+\frac{7}{12}$

Now, we again want to make it so the denominators are the same. (Here's a similar proof but for addition this time: $\frac{a}{b}+\frac{c}{b}=a\frac{1}{b}+c\frac{1}{b}=(a+c)\frac{1}{b}=\frac{a+c}{b}$ ). Now, to make the denominators the same, we can multiply the first fraction, 1/4, by 3/3 (also equivalent to 1). Doing this, we get:

$\frac{1}{4}\cdot\frac{3}{3}+\frac{7}{12}$

$\frac{3}{12}+\frac{7}{12}$

$\frac{10}{12}$ , which is equivalent to (dividing both the top and the bottom by 2) $\frac{5}{6}$ inches.

Hope this helps!

8 0

3 years ago