Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
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b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
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c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.
It is! When you're doing a fraction specifically like that, the denominators cancel out. Therefore you can get rid of the 12. It just becomes 21/7, which as you know is 3.
Hope that helps :)
Answer:
Option C
Step-by-step explanation:
Since, Price of cribs (P) are proportional to the proportional to the number of cribs (N) sold,
P ∝ N
P = kN
Here 'k' is the proportionality constant
To get the value of proportionality constant,
Since, value of 10 cribs is $1320
1320 = k(10)
k = 132
Therefore, equation will be
P = 132N
Option A
If number of cribs = 6
P = 132(6) = $792
False.
Option B
For N = 22
P = 132(22) = $2904
False.
Option C
For N = 40
P = 132(40) = $5280
True
Option D
For N = 55
P = 132(55) = $7260
False
Option E
For N = 80
P = 132(80)
= $10560
False
Option F
For N = 250
P = 132(250)
= $33000
False
If the given options have been written correctly only one option, Option (C) is correct.
Step-by-step explanation:
Here, the Taylor approximation for a square root was applied, and O(x) stands for all negligible terms of Taylor's sum with respect to variable x.
So,
b. For an increase of 2%, that is: