Answer:
Step-by-step explanation:
b=boy
a= a on the exam
b=15
b∩a=6
b'∩a=3
b'∪a'=?
b'∪a'= b'+a'-b'∩a'
a= b∩a+b'∩a (law of total probability) = 9
a'= 25-9 = 16
b'= 25-15= 10
16+10-7=19
19/25= .76
The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
Learn more about graph on:
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The closest one is 5 to the power of 1 over 3.
sq rt of 3 = 1.732
sq rt of 5 = 2.236
5^1/3 = 1.667
5^1/6 = 0.833
5^2/3 = 8.333
5^3/2 = 62.5
Answer:JKL and ∠RST are complementary.
m∠JKL = 36° and m∠RST = ( x + 15)°.
Find the value of x and the measure of ∠RST .
complementary angles are two angles whose sum is 90°
36%2Bx+%2B+15=90°
51%2Bx+=90°
x+=90-51°
x+=39°
->the measure of ∠RST== ( 39 + 15)=54°
both answer and explanation
Answer:
676
Step-by-step explanation:
d1×d2/2
42×56/2
1352/2=676
please check it by doing again
