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3 years ago

Give the domain and range of the function. Tell whether the relation is a function.

Mathematics

1 answer:

ra1l [238]3 years ago

3 0

The domain is [0,4], as the x-values go from 0 to 4.

The range is [0,4], as the y-values span from 0 to 4.

The relation is a function

- For a relation to be a function, each x-value can have only one, distinct y-value. This is the case for this relation, as each x-input has only one corresponding y output.

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What is the area of a circle with 11m and 9m?

Naya [18.7K]

Answer:

99m

Step-by-step explanation:

multiply the two numbers

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3 years ago

Choose the most convenient method to graph the line x - y = 5.

givi [52]

The most convenient method I would choose is slope-intercept form, which is y=mx+b. So, make this equation equal in terms of y.

x-y=5
subtract x from both sides
-y = 5 - x
multiply both sides by -1 so y isn't negative
y = 5 + x
5 +x is the same thing as x+5, so
y = x+5

Now, you can easily sub in any number for x and you can easily get y. Here are some points you can plot:

(0, 5), (1, 6), (2, 7), (3, 8) and the list goes on. I hope this helped!

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2 years ago

Read 2 more answers

Solve for n -4.2n-1.7=2.08

vovikov84 [41]

Answer:

n= -0.9

Step-by-step explanation:

-4.2n-1.7=2.08 ( move the constant to the right)

-4.2n = 2.08 + 1.7( calculate)

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3 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

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3 years ago

Which statement correctly compares the constant of varation of the graph and the equal below

lorasvet [3.4K]

For this there isn’t a graph showing .

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3 years ago