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Alecsey [184]
3 years ago
11

Give the domain and range of the function. Tell whether the relation is a function.

Mathematics
1 answer:
ra1l [238]3 years ago
3 0

The domain is [0,4], as the x-values go from 0 to 4.

The range is [0,4], as the y-values span from 0 to 4.

The relation is a function

- For a relation to be a function, each x-value can have only one, distinct y-value. This is the case for this relation, as each x-input has only one corresponding y output.

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Answer:

99m

Step-by-step explanation:

multiply the two numbers

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Choose the most convenient method to graph the line x - y = 5.
givi [52]
The most convenient method I would choose is slope-intercept form, which is y=mx+b. So, make this equation equal in terms of y.

x-y=5
subtract x from both sides
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multiply both sides by -1 so y isn't negative
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Now, you can easily sub in any number for x and you can easily get y. Here are some points you can plot:

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2 years ago
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Solve for n -4.2n-1.7=2.08
vovikov84 [41]

Answer:

n= -0.9

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4 0
3 years ago
According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

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3 years ago
Which statement correctly compares the constant of varation of the graph and the equal below
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For this there isn’t a graph showing .
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