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Travka [436]
3 years ago
8

3x+21 =6x-60 What is x?

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0
X = 27
Explaination: That’s the answer
vodomira [7]3 years ago
3 0
3x+21=6x-60
+60. +60
3x+81=6x
-3x. -3x
81=3x
/3. /3
27=x
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Math again :( can you help me please?
WINSTONCH [101]

Answer:

7. 8200 miles

8. $350

Step-by-step explanation:

7. The first trip nets 3400 miles; the next four trips (for a total of five) net 1200 miles each, so the total for 5 round trips is ...

... 3400 + 4×1200 = 8200 . . .  miles

8. The first month costs $100; the next 5 months (for a total of 6) cost $50 each, so the total for 6 months is ...

... $100 + 5×$50 = $350

5 0
4 years ago
To find a baseball pitcher's earned run average (ERA), you can use the formula Ei=9r, where E represents ERA, i represents numbe
Lady bird [3.3K]
You have the formula
  E i = 9 r
You can divide both sides by i and get
  E = (9 r) / i
The formula is solved for e.
5 0
4 years ago
Read 2 more answers
4) Determine the value of r so that a line through<br> the points (r, 2) and (4, -6) has a slope =
OLga [1]

This exercise is incomplete. A slope of what?

8 0
4 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
4 years ago
Solve for the length of BC
Talja [164]

Answer:

BC= 9cm

Step-by-step explanation:

  • You'll need to use the Pythagorean theorem:

a^2 + b^2 = c^2

  • 12^2 + b^2 = 15^2

The slanted side of the triangle is always going to be 'c' because it is the longest side of the triangle.

  • Now simplify:   144 + b^2 = 225

I got these numbers because 12^2= 144 and 15^2= 225

  • Subtract.   225 - 144 = 81

  • Now find the square root of 81. The answer is 9.
3 0
3 years ago
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