The area of a triangle is given by the formula

, where B is the base and h is the height. We can rearrange this formula to solve for B.

.
We plug in the given area, 640 square millimeters, and the given height, 32 millimeters.

.
40 mm is our final answer.
First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)
nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165
This will be used in the formula below
Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624
The final answer here is choice C) -624
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Answer:
1. Two ribbons, A and B. One third of A is equal to all of B. Draw a tape diagram to show the ribbons.
2. Half Robert’s piece of wire is equal to 2/3 of Maria’s wire. The total length of their wires is 10 feet. How much longer is Robert's wire than Maria's?
3. Half Sarah’s wire is equal to 2/5 of Daniel’s. Chris has 3 times as much as Sarah. In all, their wire measures 6 ft. How long is Sarah’s wire in feet?