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lions [1.4K]
2 years ago
10

What is the mass of 925.4 L of hydrogen gas at STP?

Chemistry
1 answer:
Ahat [919]2 years ago
8 0

Answer:

If this is an idea gas then 1mol takes up 22.4L.

So, knowing how many L you have you can figure out how many  mole syou have by doing a simple equation:

\frac{1mol}{y} =\frac{22.4L}{925.4L}

Solve for y.

Then, since you know how many moles you have use the ptable https://ptable.com/#Properties to figure out the mass in grams.

NOTE: The ptable tells you that 1mol of H = 1g.....so this should be an easy calculation :) enjoy

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Answer : The correct option is, (E) 7.8 atm

Explanation :

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The balanced equilibrium reaction is,

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Initial pressure     8.00      5.00            0

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The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}

Now put all the values in this expression, we get :

0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}

By solving the terms, we get:

x=0.15atm

The equilibrium partial pressure of N_2 = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of N_2 is 7.8 atm.

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